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In order to make full use of any liquid fuel, it has to be contained & controlled. Just like your lamp. As long as the rate of fuel consumption is held to a minimum, you get light for a while. If you take that same amount of fuel & light it all at once, it burns up in seconds or minutes & is gone. In order to raise the temperature, you need to add more oxygen than is in the surrounding air. If you want it to explode, you have to contain the pressurized gasses from the burn until they build up enough to rupture the containment. Kerosene burns too cold to accelerate to explosiveness without containment.
Mostly I agree. Temperature can also be raised without increasing the available oxygen density simply by storing the released heat of the combustion in high heat capacity materials, like brick and concrete.
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In the WTC incident, the only containment was the windows. Once containment was breached (almost immediately) the fuel which was already ignited & expanding, along with most of that theoretically potential stored energy, blew out into the open air & dissipated.
I simply can’t confirm that. Sixty tons of fuel is a lot of fuel to get rid of. It’s not enough volume to rise to the windows and pour out. As it vaporizes some of it will chemically combine with the oxygen carried by chimney current (referred to in our prior postings) and add its released heat into the atmosphere and into the materials of the breached floors. A lot of the vaporized jet fuel will escape. But do we have any idea of the proportion of the energy that is actually released as heat and the proportion that remains stored in the chemical bonds of the fuel?
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If it takes 60 tons of fuel to drive 4 or 5 jet engines for a few hours, under controlled conditions, where's this stored energy equal to a kiloton TNT explosion, a million KWH, or 3.6 billion BTUs? Answer: The same place it's always been. In a theoretical formula on a piece of paper or a computer screen. There's loads of stored energy everywhere. The whole trick is to get it released efficiently.
Actually the answer is that the energy is stored in the chemical bonds of the fuel. The only way to have an inefficient RELEASE of that energy is not to burn all the fuel; spill some or let some boil away…which I believe is your point. [But just in case you’re thinking something else let me remark that if all the fuel is burned (quickly, slowly, under pressure or not) ALL the energy available through oxidation will be released.] I believe your claim is that the release at the twin towers was nearly 100% inefficient. I have reservations about that claim and moreover, I propose that even 99% inefficiency releases enough heat to degrade the structure of the breached floor. On these points we seem now to be repeating ourselves. Let me be the first to admit that I haven’t added anything new to my argument in the last several posts. I’ve just been trying to make my position clear and trying to get clear on your position.
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I'm not a kid & we're not talking potentials. I was under the impression that this was a discussion of the possibilities & probabilities of what really happened in a real event.
The question is what proportion of the initially available 3.6 billion BTU of potential energy was actually released and what proportion of that was stored as heat in the materials of the building? Was the heat density high enough in key areas to generate temperatures that would degrade the structure of the breached floors? I propose that even if a small fraction of the initially available potential energy was converted and stored as heat, it would have been enough to initiate collapse. That’s why I think proper energy bookkeeping is essential here. But I just don’t know how to verify the alleged and conflicting accounts of various scenarios.
Even if I am repeating myself, it is BTW refreshing to have a real and honest discussion on this topic.